How many 12v 220ah tubular battery will be needed for a 5kva 48v solar inverter to run a load of 3600w for 12 hours?

To calculate how many 12V 220Ah tubular batteries are needed for a 5kVA 48V solar inverter to run a load of 3600W for 12 hours, follow these steps:

Step 1: Determine the Total Energy Requirement

The energy required can be calculated as:

$$\text{Energy} = \text{Power} \times \text{Time}$$

Given:

• Load power = 3600W
• Time = 12 hours

$$\text{Energy} = 3600 \, \text{W} \times 12 \, \text{hours} = 43,200 \, \text{Wh} (watt-hours)$$

Step 2: Convert the Inverter Voltage to the Required Battery Capacity

The inverter operates at 48V, so the total energy required in amp-hours (Ah) at 48V can be calculated by:

$$\text{Battery Capacity (Ah)} = \frac{\text{Energy (Wh)}}{\text{Inverter Voltage (V)}}$$ $$\text{Battery Capacity (Ah)} = \frac{43,200 \, \text{Wh}}{48 \, \text{V}} = 900 \, \text{Ah}$$

Step 3: Determine the Number of Batteries

Each battery has a voltage of 12V and a capacity of 220Ah. To achieve 48V, you need to connect 4 batteries in series (because $12V \times 4 = 48V$).

Now, to meet the required 900Ah capacity, the total Ah from the battery bank must be:

$$\text{Total Ah} = 220 \, \text{Ah (each battery)} \times \text{number of parallel strings}$$

To meet the 900Ah requirement:

$$\text{Number of parallel strings} = \frac{900 \, \text{Ah}}{220 \, \text{Ah}} = 4.09 \approx 5 \, \text{strings}$$

Step 4: Calculate the Total Number of Batteries

Each string requires 4 batteries (for 48V), and you need 5 parallel strings to achieve the desired capacity. Therefore, the total number of batteries is:

$$\text{Total number of batteries} = 4 \, \text{batteries per string} \times 5 \, \text{strings} = 20 \, \text{batteries}$$

Conclusion:

You will need 20 batteries (12V 220Ah) to run a 5kVA 48V solar inverter with a 3600W load for 12 hours.